Archive for the ‘Life Story’ Category

Photo on 12-24-17 at 8.26 AM.jpg

here’s the seasonal doo-dads again,
updated. more stuff. also the bob
dylan section has been relocated;
visible but unrecognizable from here
are some CDs & cassettes, a bunch of
books, and an LP-sleeve with cover
art from several early albums. bob
is god around here. other artists
have (smaller, lesser) such sections
back in the audio-files room (where
most of this stuff was hitherto).
all this just to the right of the
mirror. there’s a foreign-language
section in there too.

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Photo on 12-24-17 at 8.28 AM.jpg

self portrait with comix stuff & art
supplies. happy days, everybody!

mis en abyme

w’edia.

i’ve been doing more shelving lately
even than usual… even unto moving
around actual shelves. whereupon,
strictly speaking, one is “decorating”
(rather than “shelving”, rightly so-
-called). but, then again. “all the
arts are one art”, as the saying goes
(or eventually will, if i get my way).

anyhow, here’s a shot about stuff about
the former “jugoslavia” (Југославија).
also some random furniture and whatnot.
you can see the mac whose built-in camera
took all three shots (in about the middle
of the mirror). here‘s a shot from
2010 with a different macbook & camera.

the way we live now

get away from me with your phony sympathy
i can see what you want in your eyes…
get away from me with your lies
(2009; now with much smarmy spam).

photo-on-11-9-16-at-2-39-pm

 

 

adage confirmed

photo-on-9-18-16-at-12-20-pm

there is, indeed, one more fly
caught in the honey here than
in the entire collection of flies
i’ve ever caught in vinegar. also,
by one of those weird coincidences,
there’s a vinegar bottle right next
to the inverted honeybear. if the
lid had been airtight, all the goop
would’ve settled to the bottom with-
out making it quite so *damn* far… and
wasting a bunch of food and a little
time. and a fly, of course.

skynet wins; lifeforms lose.
so what. serves ’em right.
mostly.

meanwhile. i’m still trapped
in this stinking painful “body”
until the payoff. so what.

(more embarrassing whining
edited out here a few hours
after the original posting
of this piece)

seven times seven (e.g.)

7 principles (UU) the hymnal
7 days (_genesis_ & dylan) gods & traditions
7 seals (& churches; _revelation_) pointless lies
7 planets (& 7 “sisters” [“pleiades”]) science & mysticism
7 ages of man (_as_you_like_it [act 2, scene 7]) whining schoolboy; mere oblivion
7 deadly sins (dylan again [wiburys]; PALEGAS) i’m confident, you’re proud, he’s arrogant
7 colors (ROYGBIV & MRBGPYO) i have no idea what this means; leave me alone

too many is never enough

7 notes of the (major scale)

big theme: arts & sciences
(we UU’s are print junkies;
our strength & our weakness)

7 dwarves of _snow_white_ (who knows?)

(more self-pitying drivel cut here)

skynet permitting

i’m planning on a campus trip monday
so look for me at bernie’s afterwards.
i might even stay for the monday medley.
anyhow, *i’ll* plan on banging around
a bit out on the smoker’s deck or what-
not.

about the author

Photo on 2014-04-07 at 02.45

i’m going to SPACE next week.

it’s columbus ohio, so the list
narrows down pretty quick:
the “arnold classic”, SPACE,
and, um, let’s see… there
*must* have been something
else…

“ameriflora”, maybe, in your
dreams. “miracle mile”, back
from the “miracle” days of
the long-gone late-great
thriving american working class
that shopped (until it dropped)
there. no. never mind.

the chief attraction of columbus
for *me* is that this is where
i *am* (moving around… or
even moving *stuff* around…
is *much* harder than they’d
have you believe…; & of course
the *next* best thing about
columbus is that *madeline*
lives here (and our happy home
*is* our happy home, much to
my surprise). and *staying*
here keeps me this way (happy).
it’s (1) cold (2) cruel
world (3) out there.

the (very existence of)
the billy ireland museum is,
enough to put columbus *somewhere* on
the comics “map”… and there’s already
a better list of local-and-quasi-nearby
talent at the “space” site… so let
me just give a shout-out to ray (!!) t
and “max ink” (still working as far as
i know); one more for glen brewer (even
though i think glen has quit the scene;
his _askari_hodari_ was, for me, very
much a local highlight).

everybody knows about _bone_;
it won’t escape my notice here
that the astonishing paul hornschemeier
lived here, too, when he was getting
started and i met him (and he drew
a cover for my zine gratis… eat
your hearts out). in fact, ghod
*bless* columbus. good night.

i’ve typeface-ized the “formula” stuff
but the point here is the english.
tonight i encountered the passage

Since there are (p-1)/2 quadratic residues & 1^2, 2^2, …, [(p-1)/2)]^2 are all the residues, we need to show that the quadratic residues modulo p are all distinct…

and, after much wailing and gnashing
of teeth, decided that the best spin
i could put on it would be
to *omit* the first “the*
and to replace the second “the”
with “these”:
Since there are (p-1)/2 quadratic residues & 1^2, 2^2, …, [(p-1)/2)]^2 are all residues, we need to show that these quadratic residues modulo p are all distinct…

(which “works” in its context
as the original passage certainly
does *not*).

they should give medals for this kind
of copyediting. this is *hard work*.
not that it does anyone any *good*,
mind you…

today’s writing project.
i played guitar (and even talked a little)
in church today, too, so it’s been
a pretty productive day for a sunday.
(i suppose. now that i think about it,
monday morning deadlines have led me
to many a *highly* productive sunday
here at the grading table. and grading
is the actual *work*…)
********************************************
Let f(x) = x^3 + x + 57.
(Find all x s.t.
f(x)\equiv 0 (mod 125).
)
Since 125=5^3, we begin by working “mod 5”:
f(0) = 57 == 2
f(1) = 59 == 4
f(2) = 67 == 2
f(3) = 87 == 4
f(4) == f(-1) == 50 == 0 (mod 5).

So f has exactly one “mod-5 root”
(namely 4) and we consider
f'(4) = 3(4)^2 + 5 = 21 == 1 \not == 0 (mod 5).
This means that 4 is a *non-singular* root.

Hensel’s Lemma (HL)
now tells us that there is
exactly one root of f (mod 125).
But now, since
f(4) = 4^3 + 4 + 57 = 125,
we are done:
x=4
is the *only* solution to f(x)==0 (mod 125).
*************************************************
Let g(x) = x^3 + 10x^2 + x + 3.
(Find all x s.t.
g(x)\equiv 0 (mod 27).
)
Since 27=3^3, we begin by working “mod 3”:
g(0)==0
g(1)==0
g(2)==2 (mod 3).
Next, we’ll compute g'(x) = 3x^2 + 20x + 1
and evaluate it at each of our “mod 3” roots:
g'(0) =1 and g'(1) = 24 == 0 (mod 3).

The root at 1 is *singular*
(so “HL” isn’t helpful).
If “1” were lifted to a mod-9 root, x,
we would have x \in {1 +k*3} = {1, 4, 7}.
But
g(1) = 15 == 6,
g(4) = 231 == 1, and
g(7) = 843 == 6 (mod 9),
so there is *no* mod-9 root of f
satisfying x == 1 (mod 3)
(and so certainly no such mod-27 root).

The root at 0 is *non*-singular.
Since g'(0) = 1, its “mod-3 inverse” is
\bar{g'(0)} = 1.
“Plugging in” on “Hensel’s Formula”
(we have a_j = a_1 = a = 0;
our “f” is called “g”)
a_{j+1} = a_j – f(a_j)\bar{f'(a)}
(Display 2.6 of [NZM]) gives us
a_2 = 0 – 3(1) == -3 == 6 (mod 9).

Repeating the process,
a_3 = a_2 – g(a_2)\bar{g'(a)}
a_3 = 6 – 585(1)
a_3 = -579
a_3 = -(21*27 + 12).
a_3 == -12 == 15 (mod 27).
Our one-and-only solution
to f(x)==0 (mod 27) is x = 15.

(The result checks readily
[a calculator is helpful]:
f(15) = 5643 = 209*27 == 0 (mod 27).)
*************************************************